Statistics - Poisson
2009-09-26 1:12 am
回答 (2)
2009-09-26 8:23 pm
✔ 最佳答案
(b) X~Poi(λ)λ=1.3 calls/min.P(X=0)=e^(-1.3)=0.2725
(c) P(X>=3)=1-P(X=0)-P(X=1)-P(X=2)=1-0.2725-0.3543-0.2303
=0.1429
(d) Notice that P(X=8)=5.5137*10^(-5)<0.0001
So the maximum number of hone calls is 7
2009-09-26 2:20 am
設該最大數為 N，即有
P(0) +P(1) + ... + P(N-1) < 99.99%
P(0) +P(1) + ... + P(N) > = 99.99%
如果只是估算，即有
P(N+1) < (1 -99.99%) = 0.0001
P(N) > = 0.0001
所以可設
P(x) = 0.0001
即有
N = [x]+1
P(0) +P(1) + ... + P(N-1) < 99.99%
P(0) +P(1) + ... + P(N) > = 99.99%
如果只是估算，即有
P(N+1) < (1 -99.99%) = 0.0001
P(N) > = 0.0001
所以可設
P(x) = 0.0001
即有
N = [x]+1
收錄日期: 2021-04-22 00:45:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090925000051KK00894