2x-(3plus(x-5))=6. Solve the equation please!!!!!?
回答 (5)
✔ 最佳答案
2x-(3plus(x-5))=6
2x-(3+(x-5))=6
2x-(3+x-5)=6
2x-(x-2)=6
2x-x+2=6
x+2=6
x=6-2
x-=4
2x - [ 3 + ( x - 5 ) ] = 6
2x - [ x - 2 ] = 6
x + 2 = 6
x = 4
2x-(3+(x-5))=6
2x-(3+x-5)=6
2x-3-x+5=6
2x-x=6+3-5
x=4
2x - {3 + (x - 5)} = 6
2x - (3 + x - 5) = 6
2x - 3 - x + 5 = 6
x + 2 = 6
x = 4.
2x - [3 + (x - 5)] = 6
2x - [3 + x - 5] = 6
2x - [x + 3 - 5] = 6
2x - [x - 2] = 6
2x - x + 2 = 6
x = 6 - 2
x = 4
收錄日期: 2021-05-01 12:47:44
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