A manufacturer borrowed $120000 to be repaid after 3 years. The annual rate of compound interest was 9%.
Calculate the amount of interest for each year and the amount owing at the end of each year.
Simple and Compound Interests
2009-09-25 4:13 am
回答 (2)
2009-09-25 4:24 am
✔ 最佳答案
first year= 120000*9%=$10800Second year= (120000+10800)*9%=$11772
Third year =(120000+10800+11772)*9%=$12831.48
Total amount owing= 120000+10800+11772+12831.48=$155403.48
2009-09-25 4:21 am
The interest for the 1st year
= $120,000 * 9% = $10,800
The amount owing at the end of the 1st year = 120000 + 10800 = $130,800
The interest for the 2nd year
= $130,800 * 9%
= $11,772
The amount owing at the end of the 2nd year = 130800 + 11772 = $142,572
The interest for the 3rd year
= $142,572 * 9%
= $12,831.48
The amount owing at the end of the 2nd year = 142572 + 12831.48
= $155,403.48
2009-09-24 20:27:04 補充：
Typo correction:
The amount owing at the end of the 3rd year = 142572 + 12831.48
= $155,403.48
= $120,000 * 9% = $10,800
The amount owing at the end of the 1st year = 120000 + 10800 = $130,800
The interest for the 2nd year
= $130,800 * 9%
= $11,772
The amount owing at the end of the 2nd year = 130800 + 11772 = $142,572
The interest for the 3rd year
= $142,572 * 9%
= $12,831.48
The amount owing at the end of the 2nd year = 142572 + 12831.48
= $155,403.48
2009-09-24 20:27:04 補充：
Typo correction:
The amount owing at the end of the 3rd year = 142572 + 12831.48
= $155,403.48
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