請再解答以下算式，謝謝！
- (Y+1) = (1/3)Y { [(4/3)Y]+1 }
- (Y+1) = (1/3)Y { [(4/3)Y]+1
2009-09-25 1:37 am
回答 (1)
2009-09-25 3:48 am
✔ 最佳答案
- (Y+1) = (1/3)Y { [(4/3)Y]+1 }
- (Y+1) = (4/9)(Y^2) + (1/3)Y
(4/9)(Y^2) + (4/3)Y + 1 = 0
4Y^2 + 12Y + 9 = 0
(2Y + 3)^2 = 0
2Y + 3 = 0
Y = -3/2
收錄日期: 2021-04-21 22:03:17
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090924000051KK00999