Determine the discriminant of 2x^2 - 3x + 1 = 0?

2x^2 - 3x + 1 = 0
x = [-b ±√(b^2 - 4ac)]/(2a)

a = 2
b = -3
c = 1

x = [3 ±√(9 - 8)]/4
x = [3 ±√1]/4
(answer C)

use the quadratic formula

9 - 8 = 1

OPTION C