Determine the discriminant of x^2 = 4?

The discriminant is: b^2 - 4ac

Can you put this quadratic equation in standard form ?

ax^2 + bx + c = 0

Go for it. You can do it.

QED

b^2 - 4ac = 16

sorry I don't discriminate

x^2 - 4 = 0

b^2 - 4a c
0 - ( 4 ) ( 1 ) ( - 4 ) = 16

OPTION B

x^2 -4 = 0
b² - 4ac is the discriminant; b = 0, the discriminant is -4ac = 16

Answer: B

http://www.mathnstuff.com/math/spoken/here/2class/320/quadequ.htm

x^2 - 4 = 0
Get the constant
a = 1
b = 0
c = -4

formula b^2 - 4ac
0 - 4(1)(-4) = 16
the answer is b. 16

x^2 = 4
x^2 - 4 = 0
x^2 + 0x - 4 = 0
x = [-b ±√(b^2 - 4ac)]/(2a)

a = 1
b = 0
c = -4

x = [0 ±√(0 + 16)]/2
x = [0 ±√16]/2
(answer B)

Hint:

x^2=4 implies x^2+0x-4=0

x^2 + 0x -4=0
discriminant is (b^2-4ac)
(0-4*1*-4)
16