Find the solutions of x^2 + 7x = -12.?
回答 (9)
2009-09-23 3:31 pm
✔ 最佳答案
x^2 + 7x = -12x^2+7x+12=0
(x+4)(x+3)=0
x+4=0 x+3=0
x=-4 x=-3
x={-4,-3} answer//
2009-09-27 9:40 pm
x^2 + 7x + 12 = 0
( x + 4 ) ( x + 3 ) = 0
x = - 4 , x = - 3
( x + 4 ) ( x + 3 ) = 0
x = - 4 , x = - 3
2009-09-23 10:43 pm
x^2 + 7x = -12
x^2 + 7x + 12 = 0
x^2 + 7x + 12 = 0
(x + 4) (x + 3) = 0
x = -4 or x = -3
x^2 + 7x + 12 = 0
x^2 + 7x + 12 = 0
(x + 4) (x + 3) = 0
x = -4 or x = -3
2009-09-23 10:32 pm
x^2+7x+12=0
(x+3)(x+4)=0
x=-3 or -4
(x+3)(x+4)=0
x=-3 or -4
2009-09-23 10:31 pm
x^2 + 7x = -12
x^2 + 7x + 12 = 0
x^2 + 4x + 3x + 12 = 0
(x^2 + 4x) + (3x + 12) = 0
x(x + 4) + 3(x + 4) = 0
(x + 4)(x + 3) = 0
x + 4 = 0
x = -4
x + 3 = 0
x = -3
â´ x = -4, -3
x^2 + 7x + 12 = 0
x^2 + 4x + 3x + 12 = 0
(x^2 + 4x) + (3x + 12) = 0
x(x + 4) + 3(x + 4) = 0
(x + 4)(x + 3) = 0
x + 4 = 0
x = -4
x + 3 = 0
x = -3
â´ x = -4, -3
2009-09-23 10:27 pm
This is a cheat; you should learn to work the quadratic formula yourself, but here's a web site that will do the work for you. http://www.1728.com/quadratc.htm.
The first answer is correct.
The first answer is correct.
2009-09-23 10:25 pm
if you want help with your math homework your in the wrong place
2009-09-23 10:23 pm
Add 12 to both sides of the equation to get:
x^2 + 7x + 12 = 0. Now factor the polynomial. Find two numbers that when multiplied = +12 and when added = +7. Try 3 and 4.
(x + 4)(x + 3) = 0. Set each binomial to 0 and solve for x.
x + 4 = 0. x = -4. Answer
x + 3 = 0. x = -3. Answer.
Check your answers by putting each value of x in the original equation.
x^2 + 7x + 12 = 0. Now factor the polynomial. Find two numbers that when multiplied = +12 and when added = +7. Try 3 and 4.
(x + 4)(x + 3) = 0. Set each binomial to 0 and solve for x.
x + 4 = 0. x = -4. Answer
x + 3 = 0. x = -3. Answer.
Check your answers by putting each value of x in the original equation.
參考: Self
2009-09-23 10:19 pm
x^2 + 7x = -12 [put into standard form]
x^2 + 7x + 12 = 0 [factor]
(x+4)(x+3) = 0 [set each factor to zero]
(x+4) = 0 OR (x+3) = 0 [solve each factor for x]
x = -4 OR x = -3
voila
x^2 + 7x + 12 = 0 [factor]
(x+4)(x+3) = 0 [set each factor to zero]
(x+4) = 0 OR (x+3) = 0 [solve each factor for x]
x = -4 OR x = -3
voila
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