Find the solutions of x^2 + 7x = -12.?

x^2 + 7x = -12
x^2+7x+12=0
(x+4)(x+3)=0
x+4=0 x+3=0
x=-4 x=-3

x={-4,-3} answer//

x^2 + 7x + 12 = 0

( x + 4 ) ( x + 3 ) = 0

x = - 4 , x = - 3

x^2 + 7x = -12

x^2 + 7x + 12 = 0

x^2 + 7x + 12 = 0
(x + 4) (x + 3) = 0

x = -4 or x = -3

x^2+7x+12=0

(x+3)(x+4)=0

x=-3 or -4

x^2 + 7x = -12
x^2 + 7x + 12 = 0
x^2 + 4x + 3x + 12 = 0
(x^2 + 4x) + (3x + 12) = 0
x(x + 4) + 3(x + 4) = 0
(x + 4)(x + 3) = 0

x + 4 = 0
x = -4

x + 3 = 0
x = -3

∴ x = -4, -3

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The first answer is correct.

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Add 12 to both sides of the equation to get:

x^2 + 7x + 12 = 0. Now factor the polynomial. Find two numbers that when multiplied = +12 and when added = +7. Try 3 and 4.

(x + 4)(x + 3) = 0. Set each binomial to 0 and solve for x.

x + 4 = 0. x = -4. Answer

x + 3 = 0. x = -3. Answer.

Check your answers by putting each value of x in the original equation.

x^2 + 7x = -12 [put into standard form]
x^2 + 7x + 12 = 0 [factor]
(x+4)(x+3) = 0 [set each factor to zero]
(x+4) = 0 OR (x+3) = 0 [solve each factor for x]
x = -4 OR x = -3

voila