F.4 Quadratic Equation

2009-09-24 4:37 am
1. It is given that k is a root of the quadratic equation x^2 + x + c = 0.
(a) Express c in terms of k.
Solution:
x^2 + x + c = 0
k^2 + k + c = 0
c = -k^2 - k
(b) Find the other root of the equation in (a).
How to do so? And explain the steps clearly. Thanks a lot.
更新1:

root one +root two = - b/a root one x root two = c/a I just find this two principles to solve this equation How come?

更新2:

they are related to product of roots and sum of roots They are Chapter 2 in my maths book but the question is in Chapter 1

更新3:

Hence, I can just only solve the quadratic equation by factor method, quadratic formula, graphical method

更新4:

Sol: For the curve x^2 + x + c = 0 By using Quadratic formula, - 1 ± √[1-4(1)(c)] / 2(1) =- 1 ± √[1-4(-k^2 - k) / 2 =- 1 ± √(1+4k^2 +4k) / 2 =- 1 ± √(2k+1)^2 / 2 =- 1 + (2k+1) / 2 or - 1 - (2k+1) / 2 = k or -k - 1 The other root is - k - 1

回答 (1)

2009-09-24 4:43 am
✔ 最佳答案
In part a, you find out that c = -k2 - k

b. Let the other root be m.

The equation is: x2 + x - (k2 + k) = 0

We consider the sum of roots, m + k = -1

Therefore, m = -k - 1

Or we may consider the product of roots, mk = -(k2 + k)

m = -k - 1



2009-09-23 20:45:01 補充:
I realize that it is a g.math question.

So, I would rather use another method.

Let m be the other root.

So, the equation can be expressed as (x - k)(x - m) = 0

x^2 - (k + m)x + km = 0

So, using the same method as I used.
參考: Physics king


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