2.5千瓦220v的電熱水器..其電阻值等於多少?
我想知計法.... thx
急~~ 就快要考試...幫幫手
2009-09-23 7:13 am
回答 (3)
2009-10-02 1:14 am
電熱水器的電阻值為R= V ^ 2 / P = 220 ^2 / 2500 = 19.2 OHM
或用另一式 I = P /V = 2500 / 220 = 11.36A R = V / I = 220 / 11.36A = 19.2 OHM
或用另一式 I = P /V = 2500 / 220 = 11.36A R = V / I = 220 / 11.36A = 19.2 OHM
2009-09-24 12:58 am
同我書答案有出入....我知答案不過計唔到....書寫答案係16歐姆
2009-09-23 7:34 am
R= E 2 /P
R=220X220/2500
=19.36歐姆
驗算 :
P= E2 R
P=220X220/19.36
=2500W
R=220X220/2500
=19.36歐姆
驗算 :
P= E2 R
P=220X220/19.36
=2500W
收錄日期: 2021-04-23 18:20:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090922000051KK01845