求液壓系統工作原理 - Ans.fyi 參考答案

求液壓系統工作原理

Oliver_915

2009-09-22 7:30 am

液壓系統例如油壓臂等是如何靠液體將輸入的壓力放大數千倍然後再將這壓力輸出的？
希望能解釋得具體一點，例如輸入液體壓力接觸面積跟輸出液體壓力接觸面積比率與提升壓力的關係等。

回答 (1)

天同

2009-09-23 4:01 am

✔ 最佳答案

Hydraulic systems are, in fact, a kind of machine. Using the principle of machine, assume 100% efficiency, the energy output = energy input.
Hence, energy input = effort x distance moved by effect = (P.A).d
where P is the pressure at the effort end, A is the cross-sectional area, and d is the distance moved by the effort
Energy output = load x distance moved by load = (P'.A').d'
where P', A' and d' are the pressure, cross-sectional area and distance moved respectively at the load end.
Thus, (P.A).d = (P'.A').d'
i.e. (P'.A')/(P.A) = (d/d')
Gererally, in a hydraulic machine, A'>A, and d'<d, thus the effort needed (P.A) can be much smaller than the load (P'.A')

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