F.4 熱學(1條簡單題目 10分)

2009-09-21 5:50 am
A faulty thermometer with uniform scale reads 10 C and 90 C when it is placed in melting ice and steam over boiling water respectively. What should be the true temperature if the thermometer reads 40 C?
* Please show the calculation steps clearly.

回答 (3)

2009-09-21 5:25 pm
✔ 最佳答案
When actual temperature difference is 100 C, the temperature difference shown on the thermeter is 80 C.
So when the temperature difference shown on the thermeter is 40 - 10 = 30 C, the actual temperature difference should be 30 x 100/80 = 37.5 C
Hence, starting from 10 C, the thermometer reads 10 + 37.5 = 47.5 C
參考: Myself
2009-09-25 6:15 am
A easy method
10______________________________90 -A

0______________________________100 -B
Above two is the temperature range, (A) and (B) show the same
range of temperature of 1C to 100 C but in terms of different no.




10______________?________________90 -A

0_______________50______________100 -B
We know that the middle C of 0C to 100C is 50 C but we don`t know the no. in (A)
the method we calculate is use (100-0)/2
therefore we use the same method (90-10)/2=40

40 is the no. you ask ,as it is the middle no.,it is equal to 50

The Answer is 50
2009-09-22 11:52 pm
True temperature /Faulty temperature
100 C/ 90 C
y C/ 40 C
0 C/ 10 C
The faulty temperature and the true temperature are in linear relationship.
(y - 0)/(100-0)= (40- 10)/(90-10)
y = 37.5 C
If the faulty temperature is 40 C, the true temperature should be 37.5 C


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