Factorize the following.
(1) 9x^2-6xy+y^2-4x^2 y^2
[x^2 y^2=X嘅二次方和Y嘅二次方]
(2a) Expand (-a+b)(-a-b).
(2b)By using the results of (2a), expand (-2p+1+q)(-2p+1-q)
(3a) Factorize -m^2(r-1)+m-m^2
(3b) Factorize m(r-1)^2-(r-1)-m(1-r)
(3c) By using the results of (a) and (b), factorize [-m^2(r-1)+m-m^2]+[m(r-1)^2-(r-1)-m(1-r)]
F.2數學題 Factorize [救命]
2009-09-21 1:45 am
回答 (2)
2009-09-21 2:59 am
✔ 最佳答案
(1) 9x2-6xy+y2-4x2 y2 =(3x-y)2-(2xy)2
=[(3x-y)-2xy] [(3x-y)+2xy]
=(3x-2xy-y)(3x+2xy-y)
(2a) (-a+b)(-a-b)
=[-(a-b)][-(a+b)]
=(a-b)(a+b)
=a2-b2
(2b) (-2p+1+q)(-2p+1-q)
=[-(2p-1)+q)][ [-(2p-1)-q]
=(2p-1)2-q2
=4p2-4p+1-q2
=4p2-4p-q2+1
2009-09-20 19:00:01 補充：
第3題打錯？!
2009-09-22 00:06:58 補充：
(3a)-m^2(r-1)+m-m^2
=-m[m(r-1)-1+m]
=-m(mr-1)
(3b) Factorize m(r-1)^2-(r-1)-m(1-r)
= m(r-1)^2-(r-1)+m(r-1)
=(r-1)[m(r-1)-1+m]
=(r-1)(mr-1)
(3c)[-m^2(r-1)+m-m^2]+[m(r-1)^2-(r-1)-m(1-r)]
=[-m(mr-1)]+[(r-1)(mr-1)]
=(mr-1)[-m+(r-1)]
=(mr-1)(r-m-1)
2009-09-22 12:28 am
我對著本書睇左一次，好似冇打錯……唔通呢條題有問題？你原本是覺得邊度打錯？
收錄日期: 2021-04-13 16:51:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090920000051KK01408