高中化學 稀溶液的依數性

2009-09-16 7:10 am
已知60度時純丙酮之平衡蒸氣壓為800mmHg,純苯之平衡蒸氣壓為300mmHg
(1)茲由4.0mol丙酮與6.0mol苯混合所生成混合蒸氣壓為幾mmHg?
(2)收集蒸氣後然後冷凝混合蒸氣 ,再加熱至60度則再次生成混合
蒸氣壓為若干mmHg

回答 (1)

2009-09-16 7:58 am
✔ 最佳答案
(1)
丙酮:P1o = 800 mmHg, X1 = 4/(4 + 6) = 0.4
苯:P2o = 300 mmHg, X2 = 6/(4 + 6) = 0.6

根據臘烏爾定律(Raoult's law):
混合蒸氣壓 P
= P1oX1 + P2oX2
= (800)(0.4) + (300)(0.6)
= 320 + 180
= 500 mmHg


(2)
丙酮:P1o = 800 mmHg, X1 = 320/500 = 0.64
苯:P2o = 300 mmHg, X2 = 180/500 = 0.36

根據臘烏爾定律(Raoult's law):
混合蒸氣壓 P
= P1oX1 + P2oX2
= (800)(0.64) + (300)(0.36)
= 512 + 108
= 620 mmHg


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