F.5 math ASGS 問題

2009-09-16 5:41 am
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2009-09-16 6:04 am
✔ 最佳答案

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a)Perimeter of A1 = 4*1 = 4[2(1) - 1]
A2 = 4*3 = 4[2(2) - 1]
A3 = 4*5 = 4[2(3) - 1]
A15 = 4[2(15) - 1] = 116cm
b)
The area of A1 = 1 = 2(1) - 1
A2 = 1 + 3 + 1 = 1 + 2(2) -1 + 1
A3 = 1+ 3 + 5 + 3 + 1 = 1 + 3 + 2(3)-1 + 3 + 1
A15 = 1 + 3 + 5 + 7 + 9 + 11 + ... + 27 + 2(15)-1 + 27 + 25 +... + 1
= 2*(1+3+5+7+...+27) + 29
= 2*(1+27)14/2 + 29
= 421cm2



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