trig Limits

2009-09-15 1:31 pm
Find the limits
lim arctan (x^6-x^8)
x->infinity

回答 (1)

2009-09-15 3:30 pm
✔ 最佳答案
This time, we consider lim (x→infinity) (x6 - x8) = - infinity

So, lim (x→infinity) tan-1(x6 - x8)

= -pi / 2

Remember x is taken the value in radian.

And tan(-pi/2) = - infinity

參考: Physics king


收錄日期: 2021-04-19 15:22:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090915000051KK00132

檢視 Wayback Machine 備份