need help with solving equations?

2009-09-15 1:40 am
i need help with these questions. 1A)3a + 2 = 17 1B)5a +24 = -6 1C) 6x - 3 = 5x + 2 1D) 4x + 7 = 3x + 3 2A) 2(b - 1) = 4 2B)4(b - 3) = 0

回答 (5)

2009-09-15 1:47 am
✔ 最佳答案
3a + 2 = 17
Subtract 2 from each side
3a = 15
Divide each side by 3
a = 5

5a + 24 = -6
Subtract 24 from each side
5a = -30
Divide each side by 5
a = -6

6x - 3 = 5x + 2
Subtract 5x from each side
x - 3 = 2
Add 3 to each side
x = 5

4x + 7 = 3x + 3
Subtract 3x from each side
x + 7 = 3
Subtract 7 from each side
x = -4

2(b-1) = 4
2b - 2 = 4
Add 2 to each side
2b = 6
Divide each side by 2
b = 3

4(b-3) = 0
4b - 12 = 0
Add 12 to each side
4b = 12
Divide each side by 4
b = 3
2009-09-15 8:51 am
1a....
3a+2= 17 subract 2 from each side
3a= 15 divide each side by 3
a = 5

1b......
5a+24=-6 subtract 24 from each side
5a= -30 divide each side by 5
a= -6

1c.....
6x-3=5x+2 subract each side by 5x
x-3=2 add each side by 3
x= 5

1d....
4x+7 = 3x+3 subtract each side by 3x
x+7=3 subract each side by 7
x= -4

2b....
4(b-3)=0 distribute the 4 throughout the parenthesis
4b-12=0 subtract each side by 12
4b = 12 divide each side by 4
b=3
參考: pay attention in class next time, cuz this is soo easy. and try to learn how i got my answer
2009-09-15 8:45 am
a) a = 5
b) a = -6
c) x = 5
d) x = - 4
2a) b = 3
b) b = 3
2009-09-15 8:44 am
1A Subtract 2 from both sides to get 3a=15
Divide by 3 to get a=5

B) Subtract 24 form both sides to get 5a = -30
Divide by 5 to get a=-6

and so on
2009-09-15 8:44 am
1A) 3a + 2 = 17
3a=15
a=5

1B) 5a +24 = -6
5a=-30
a=-6


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