我中四,呢題數唔識計,唔該大家幫我手.
題數就係咁:(4x-5)*2=(x-9)(4x-5)
回答 (2)
(4x-5)*2=(x-9)(4x-5)
left 調過 right
0=(x-9)(4x-5) - (4x-5)*2
0=(4x-5)[(x-9)-2]
0=(4x-5)(x-11)
so: x=11 or 5/4
參考: me
(4x-5)*2=(x-9)(4x-5)
8x -10 = 4x^2 -5x -36x +45
調過來::
4x^2 + 49x -45 =0
用cross method / quadratic 做 solve左佢
個答案要用quadratic formula 計
參考: 自己
收錄日期: 2021-04-13 16:51:58
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