AL Phy max. possible error
2009-09-12 6:31 pm
Use differentials to approximate maximum possible error of a rectangle where length l =3.75±0.01m and breadth b=1.83±0.01m
回答 (2)
2009-09-12 6:37 pm
✔ 最佳答案
Are you finding the maximum possible error of the area of the rectangle?As area, A = bl
│@A/A│ = │@b/b│+│@l/l│
= │0.01/1.83│+│0.01/3.75│
= 0.004
So, the maximum possible error is 0.004 X 100% = 0.4%
參考: Physics king
2009-09-12 8:58 pm
Normal way is:
dA/A = Sqrt[ (dl/l)^2 + (db/b)^2 ]
Coz it is 2-dimensional, use absolute value will often result larger error.
dA/A = Sqrt[ (dl/l)^2 + (db/b)^2 ]
Coz it is 2-dimensional, use absolute value will often result larger error.
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