Heat KE

For a given temperature, the K.E. of a molecule is fixed, it is given by K.E. = 3/2 kT, where k is the Boltzmann's constant, T is the absolute temperature. The K.E. depends on temperature only.

So, the statement K.E. of oxygen > K.E. of hydrogen is wrong.


x and y are equal in quantity, but that doesn't mean that they are necessary having the same intermolecular potential energy.

So, the statement x has more internal energy than y is false.

Since internal energy = molecular K.E. + intermolecular P.E.

Although the molecular K.E. of x is higher than y (temperature is higher), we can't tell which intermolecular P.E. is higher.

唔肯定咩系8times more massive, 不過呢
temperature is defined as the "Averge kinetic energy" 所以如果系oxygen數量有8倍~Average kinetic energy ie.etemperature 一樣 total kinetic energy咪多d~不過如果純粹系oxygen既重量比hydrogen重咁樣就無關係咯~

internal energy= K.E.+P.E.
K.E.方面 x多d...因為average kinetic energy （temperature）多d但系quantity一樣~
咁樣P.E.呢 就要考慮系咩物質~因為萬一y既boiling好低...距系gas而x系liquid的話...咁樣y既p.e.就多過x啦~所以呢~其實答案應該系唔知架 除非..距比substance你..或者話系一樣substance... ;)