if(3x+1)(2x-5)=Ax square+Bx+C,find the constants A,B,C
要有steps,唔該哂
f.2簡單數學
2009-09-11 7:44 am
回答 (2)
2009-09-11 7:57 am
✔ 最佳答案
(3x + 1)(2x - 5)= 3x(2x - 5) + (2x - 5)
= 6x^2 - 15x + 2x - 5
= 6x^2 - 13x - 5
Comparing coefficients, A = 6; B = -13 and C = -5
2009-09-11 8:03 am
L.H.S.= (3x+1)(2x-5)
= 6x square -15x +2x -5
= 6x square -13x -5
By comparing the coefficient, A=6, B=-13, C=-5.
= 6x square -15x +2x -5
= 6x square -13x -5
By comparing the coefficient, A=6, B=-13, C=-5.
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