Factorize: 8 - (x + h)^3?
回答 (4)
2009-09-09 11:20 am
✔ 最佳答案
8 - (x + h)^3=[2-(x+h)][4+2(x+h)+(x+h)^2]
=[2-x-h][4+2x+h+x^2+2hx+h^2]
=-(h+x-2)(h^2+2hx+2h+x^2+2x+4) answer//
2009-09-09 6:10 pm
8 = 2^3 so
2^3 - (x + h)^3
Remember that a^3-b^3 = (a-b)(a^2+ab+b^2)
(2-x-h)[4+2(x+h)+(x+2)^2]
(2-x-h)(4+2x+2h+x^2+4x+4)
(2-x-h)(x^2+6x+2h+8)
2^3 - (x + h)^3
Remember that a^3-b^3 = (a-b)(a^2+ab+b^2)
(2-x-h)[4+2(x+h)+(x+2)^2]
(2-x-h)(4+2x+2h+x^2+4x+4)
(2-x-h)(x^2+6x+2h+8)
2009-09-09 6:12 pm
a^3-b#=(a-b)(a^2+ab+b^2)
2^3-(x+h)^3
= ( 2-x-h)[ 4+ 2(x+h)+ (x+h)^2]
2^3-(x+h)^3
= ( 2-x-h)[ 4+ 2(x+h)+ (x+h)^2]
2009-09-09 6:10 pm
8 - (x + h)^3
= 2^3 - (x + h)^3
= [2 - (x + h)][2^2 + 2(x + h) + (x + h)^2]
= [2 - x - h][4 + 2(x + h) + (x + h)^2]
= 2^3 - (x + h)^3
= [2 - (x + h)][2^2 + 2(x + h) + (x + h)^2]
= [2 - x - h][4 + 2(x + h) + (x + h)^2]
收錄日期: 2021-05-01 12:46:41
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