分解ax+2ay+bx+2by為因式
化簡(a+b)2次方-(a-b)2次方
因式分解
1.x(2次方)-9
2.ac+bc-ad-bd
3.x(2次方)-(y-z)2次方
要有過程
急~有數學唔識做？？
2009-09-10 7:06 am
回答 (1)
2009-09-10 7:28 am
✔ 最佳答案
ax+2ay+bx+2by=ax+bx+2ay+2by
=x(a+b)+2y(a+b)
=(x+2y)(a+b)
(a+b)2-(a-b)2
=[(a+b)-(a-b)][(a+b)+(a-b)]
=2b(2a)
=4ab
1.x2-9
=(x-3)(x+3)
2.ac+bc-ad-bd
=c(a+b)-d(a+b)
=(c-d)(a+b)
3.x2-(y-z)2
=[x-(y-z)][x+(y-z)]
=(x-y+z)(x+y-z)
收錄日期: 2021-04-23 20:38:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090909000051KK01917