Sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl) to give sodium chloride (NaCl) and carbonic acid?
2009-09-08 8:31 pm
Sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl) to give sodium chloride (NaCl) and carbonic acid (H2CO3). The carbonic acid rapidly breaks down to give carbon dioxide and water, leaving the solution neutral. Write and balance the chemical equation and then calculate; "how many moles of HCl are required to react with 0.050 moles of sodium carbonate?"
回答 (4)
2009-09-08 8:35 pm
✔ 最佳答案
Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2Othe ratio between Na2CO3 and HCl is 1 : 2
moles HCl required = 0.050 x 2=0.10
2009-09-08 9:03 pm
Balanced eqn is Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O
106gm(1mole) of Na2CO3 reacts with 73gm(2moles) of HCl.
0.050mole or 5.3gm of Na2CO3 reacts with HCl= (73/106)*5.3= 3.65gm or 0.10 mole
106gm(1mole) of Na2CO3 reacts with 73gm(2moles) of HCl.
0.050mole or 5.3gm of Na2CO3 reacts with HCl= (73/106)*5.3= 3.65gm or 0.10 mole
參考: My knowledge
2016-02-11 5:05 pm
when sodium carbonate reacts with HCL IT GIVE BRISK EFFERENCE THAT IS CO2 BUBBLES
GIVES A COLOURLESS ODOURLESS GAS
THE COLOURLESS LIME WATER TURNS MILKY
GIVES A COLOURLESS ODOURLESS GAS
THE COLOURLESS LIME WATER TURNS MILKY
2016-02-04 3:07 pm
234 grams A+ answer
收錄日期: 2021-04-21 19:11:23
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