maths. x6Q

2009-09-08 5:54 am
1. k^2=16k

2. 9y^2-16=0

3. 2t^2+5t+3=0

4. (a-2)(a+2)=15a/2

5. (4-x)^2-5(4-x)-14=0

6. (2x+3)^2=x(2x+33)

回答 (2)

2009-09-08 6:16 am
✔ 最佳答案
1. k2 = 16k
k2 - 16k = 0
k(k - 16) = 0
k = 0 or k - 16 = 0
k= 0 or k =16
2. 9y2 - 16 = 0
(3y + 4)(3y - 4) = 0
3y + 4 = 0 or 3y - 4 = 0
y = -4/3 or y = 4/3
3. 2t2 + 5t + 3 = 0
2t2 + 3t + 2t + 3 = 0
t(2t + 3) + (2t + 3) = 0
(2t + 3)(t + 1) = 0
2t + 3 = 0 or t + 1 = 0
t = -3/2 or t = -1
4. (a - 2)(a + 2) = 15a/2
a2 - 4 - 15a/2 = 0
2a2 - 15a - 8 = 0
2a2 + a - 16a - 8 = 0
a(2a + 1) - 8(2a + 1) = 0
(a - 8)(2a + 1) = 0
a - 8 = 0 or 2a + 1 = 0
a = 8 or a = -1/2
5. (4 - x)2 - 5(4 - x) - 14 = 0
Let 4 - x = u
u2 - 5u - 14 = 0
u2 - 7u + 2u - 14 = 0
u(u - 7) + 2(u - 7) = 0
(u + 2)(u - 7) = 0
(4 - x + 2)(4 - x - 7) = 0
(6 - x)(-x - 3) = 0
6 - x = 0 or - x - 3 = 0
x = 6 or x = -3
6. (2x + 3)2 = x(2x + 3)
(2x + 3)2 - x(2x + 3) = 0
(2x + 3)(2x + 3 - x) = 0
(2x + 3)(x + 3) = 0
2x + 3 = 0 or x + 3 = 0
x = -3/2 or x = -3
2009-09-08 6:24 am
1. k^2=16k
k^2-16k=0
k(k-16)=0
k=0 or k=16

2. 9y^2-16=0
(3y-4)(3y+4)=0
y=4/3 or y=-4/3

3. 2t^2+5t+3=0
(2t+3)(t+1)=0
t=-3/2 or t=-1

4. (a-2)(a+2)=15a/2
a^2-4=15a/2
2a^2-8=15a
2a^2-15a-8=0
(2a+1)(a-8)=0
a=-1/2 or a=8

5. (4-x)^2-5(4-x)-14=0
(4-x-7)(4-x+2)=0
(-x-3)(6-x)=0
x=-3 or x=6

6. (2x+3)^2=x(2x+33)
4x^2+12x+9-2x^2-33x=0
2x^2-21x+9=0
x=(21+/-sqrt(369))/4
=(21+/-3sqrt(41))/4


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