Applications in Trigonometry2

2009-09-06 5:36 am
1. A balloon B is observed simultaneously from two points P and Q on a horizontal ground. P is at a distance of c metres due north of Q. R is the projection of B on the ground. The bearings of the balloon from P and Q are Sα゚E and Nβ゚E respectively. The angle of elevation of B from P is θ゚.

(a) If the height of the balloon is h meters, show that
h = (ctanθ゚sinβ゚) / [sin(α゚ + β゚)].
(b) Given thatθ = 40, α = 54 and β = 46, find
(i) h / c,
(ii) the angle of elevation of B from Q,
(iii) the angle of elevation and the bearing of B from M, where M is the mid-point of PQ.

http://i617.photobucket.com/albums/tt257/michaelcoco_/2.jpg

※ 只需計算(b)(iii)※

The answer of (b)(iii) is:
Angle of elevation = 45.8゚, bearing = N83.2゚E

回答 (1)

2009-09-06 7:54 am
✔ 最佳答案
h/c = tan40sin46/sin100 = 0.6129
Sine rule, PR/sin46 = c/sin80
PR = c sin46/sin80 = 0.7304c
MR2 = PM2 + PR2 - 2(PM)(PR)cos54
MR2 = 0.25c2 + 0.5335c2 - 0.4293c2 = 0.3542c2
MR = 0.5951c
Angle of elevation = tan-1(h/MR)
= tan-1(h/0.5951c)
= tan-1[(h/c)/0.5951]
= tan-1(0.6129/0.5951)
= tan-1(1.03)
= 45.8
cosPMR = (PM2 + MR2 - PR2) / [2(PM)(MR)]
= (0.25c2 + 0.3542c2 - 0.5335c2) / [2(0.5)(0.5951)c2]
= 0.0707/0.5951
= 0.1188
PMR = 83.2
So bearing is N83.2E


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