-2x+3< -7 how do you solve need help!?
回答 (3)
2009-09-04 7:53 pm
✔ 最佳答案
-2x + 3 < -7-2x < -7 - 3
x > -10/(-2)
x > 5
2009-09-05 2:49 am
First get all the real numbers on one side
-2x + 3 (-3) < -7 (-3)
-2x < -10
The negatives on each side cancel each other out, and voila, it's easy.
2x < 10
You can go from here, right?
-2x + 3 (-3) < -7 (-3)
-2x < -10
The negatives on each side cancel each other out, and voila, it's easy.
2x < 10
You can go from here, right?
2009-09-05 2:48 am
-2x + 3 < -7
-2x < -10 (subtract 3 from both sides)
x > 5 (divide both sides by -2, since we are dividing by a negative number we must swap the < to a >)
-2x < -10 (subtract 3 from both sides)
x > 5 (divide both sides by -2, since we are dividing by a negative number we must swap the < to a >)
收錄日期: 2021-05-01 12:50:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090904114251AA3ndOp