中五升中六 chem redox 急
2009-09-04 3:44 am
A 25cm^3 portion of sodium ethanedioate solution of concentration 0.200mol dm^-3 is warmed and titrated against a solution of potassium manganate(7). if 17.2cm3 of potassium manganate(7) are required, what is its concentration?
回答 (2)
2009-09-04 5:22 pm
✔ 最佳答案
Suppose that the KMnO4 solution is with enough acidification, then according to the equation:5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) → 10CO2(g) + 2Mn2+(aq) + 8H2O(l)
2 moles of MnO4- react completely with 5 moles of C2O42- and hence:
No. of moles of C2O42- = 0.2 x 25/1000 = 0.005
No. of moles of MnO4- = 0.002
Thus, conc. of KMnO4 solution = 0.002/0.0172 = 0.1163 M
參考: Myself
2009-09-04 10:07 am
Is the potassium manganate(VII) solution acidified ?
收錄日期: 2021-05-02 00:03:54
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