1. calculate(4/3)^2x(3/4)^-3
2. calculate(2^-1+3^-1)^-1
Maths (integral indice)
2009-09-03 12:40 am
回答 (1)
2009-09-03 1:06 am
✔ 最佳答案
(4/3)^2x(3/4)^-3=(4/3)^2 x (4/3)^3
=(4/3)^5//
(2^-1+3^-1)^-1
=(1/2+1/3)^-1
=(5/6)^-1
=6/5//
收錄日期: 2021-04-13 16:49:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090902000051KK01012