Differentiate the fuctions with respect to x
Express your answers in positive indices.
y=√(x-√(x2-1))
y等於開方(x減開方(x二次方減一))
Differentiation 一題
2009-09-01 4:43 am
回答 (2)
2009-09-01 5:17 am
✔ 最佳答案
y=√[x - √(x2 - 1)]y2 = x - (x2 - 1)0.5
2y(dy/dx) = 1 - (0.5)(x2 - 1)-0.5(2x)
2y(dy/dx) = 1 - x/(x2 - 1)0.5
2{√[x - √(x2 - 1)]}(dy/dx) = [√(x2 - 1) - x]/√(x2 - 1)
dy/dx = -0.5{√[x - √(x2 - 1)]} / √(x2 - 1)
2009-09-01 4:49 am
如果我無計錯
dy/dx = 0.5 [x - √(x^2 -1)]^-0.5 [1- 0.5(x^2 -1)^-0.5 (2x)]
dy/dx = 0.5 [x - √(x^2 -1)]^-0.5 [1- 0.5(x^2 -1)^-0.5 (2x)]
收錄日期: 2021-04-23 23:17:57
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