Equilibrium Constant

2009-09-01 1:34 am
Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture?

The answer is 0.463720087095, please show your solution clearly and steps by steps. Thank you very much~

回答 (1)

2009-09-01 3:05 am
✔ 最佳答案
Kc=61 for the reaction N2(g) + 3H2(g) → 2NH3(g) at a certain temperature. Suppose it was found that an equilibrium mixture of these gases contained 0.3284 M NH3 and 0.017730 M N2. What is the concentration of H2 in the mixture?


N2(g) + 3H2(g) ≒ 2NH3(g)

At equilibrium:
[NH3] = 0.3284 mol dm-3
[N2] = 0.017730 mol dm-3

Kc = [NH3]2/([N2]•[H2]3)
61 = (0.3284)2/(0.017730)[H2]3)

Concentration of H2 in the equilibrium mixture, [H2]
= [(0.3284)2/(0.017730)(61)]1/3
= 0.4637 mol dm-3
(to 4 sig. fig.)


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