數學方程(求步骤)(20点)(急要)(1條)

x/3-(20-x)/7=10
21[x/3-(20-x)/7]=21(10)
7x-3(20-x)=210
7x-60+3x=210
10x=270
x=270/10
x=27


or


x/3-(20-x)/7=10
[7x-3(20-x)]/21=10
7x-60+3x=21(10)
10x=210+60
10x=270
x=270/10
x=27



**建議遇到分數嘅題目,最好先搵出佢哋嘅最小公倍數,將分數嘅部份化番做整數,相對比通分母較容易處理,也沒有那麼容易出錯 =]
**留意正負加減, some careless mistakes =]
****最重要係要 double check, double check真係好緊要,明明識做,錯咗就唔抵啦 =]

解方程:

x/3-(20-x)/7=10

[7x-3(20-x)] / 21 = 10

7x-60+3x= 210

10x-60=210

10x= 210+60

10x= 270

x = 27

x/3-(20-x)/7=10
7x-3(20-x)=210
7x-60+3x=210
10x=270
x=27

我只是個F.1仔,你這題好難!!

太深,唔識做,i am just a F.1 student