how do you simplify ?

1. a^5 * a^-5 = 1, as when multiplying one number with different powers, you simply add the powers together. 1^-3 = 1
Therefore, the answer to question one is 1.

2. (3x)^3 = 27x^3
(2x)^2 = 4x^2
27x^3 * 4x^2 = (27*4)x^(2+3)
(27*4)x^5 / 4x = (27*4/4)x^(5-1) = 27x^4
(27x^4)^2 = (27*27)x^(4*2)
=729x^8

1)
[(a^-5)(a^5)]^-3
= [a^(-5 + 5)]^-3
= [a^0]^-3
= 1^-3
= 1

2)
[(3x)^3(2x^2)/(4x)]^2
= [(3x)^(3 * 2)(2^2)x^(2 * 2)]/(4x)^2
= [(3x)^6(4x^4)]/(16x^2)
= [(3x)^6(x^2)]/4

Qu 1
1

Qu 2
( 54 x^5 )^2
--------------------
16 x^2

54^2 x^10
------------------
16 x^2

(54) (54) x^8
----------------------
16


(729 / 4 ) x^8

simplify means solve
so solve it