suppose tanθ=2, find the value of (2sinθ+cosθ)/(sinθ-cosθ)
thx!!
F4 trigonometry
2009-08-30 1:33 am
回答 (2)
2009-08-30 1:38 am
✔ 最佳答案
suppose tanθ=2, find the value of (2sinθ+cosθ)/(sinθ-cosθ)(2sinθ+cosθ)/(sinθ-cosθ)
=(2sinθ/cosθ +cosθ/cosθ)/(sinθ/cosθ-cosθ/cosθ)
=(2tanθ+1)/(tanθ-1)
=(4+1)/(2-1)
= 5
2009-08-30 8:18 am
答得幾好! Why?
He can use trigonometric identical formula to solve this problem.
For example ,
1.sinθ/cosθ = tanθ
2. (sinθ^2)+(cosθ^2) = 1
總之 , 佢的解答很詳細 !
Very good !
Very well !
And very great !
In fact , trigonometric identical formula has 5 .
THESE THE 2 AMONG OF THEM .
He can use trigonometric identical formula to solve this problem.
For example ,
1.sinθ/cosθ = tanθ
2. (sinθ^2)+(cosθ^2) = 1
總之 , 佢的解答很詳細 !
Very good !
Very well !
And very great !
In fact , trigonometric identical formula has 5 .
THESE THE 2 AMONG OF THEM .
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