solve the equation: (n-5)^2 = 20?
回答 (3)
2009-08-27 5:22 pm
✔ 最佳答案
(n - 5)^2 = 20n - 5 = ±√20
n - 5 = ±√(2^2 * 5)
n = 5 ±2√5
2009-08-27 5:04 pm
(n - 5)² = 20
n² - 10n + 25 = 20
n² - 10n + 5 = 0
n = (10 ± â[100 - 20]) / 2
= 5 ± 2â5
n² - 10n + 25 = 20
n² - 10n + 5 = 0
n = (10 ± â[100 - 20]) / 2
= 5 ± 2â5
2009-08-27 5:01 pm
n= (+/- sqrt(20)) + 5
You need to take the square root of both sides. Consider the +/- then add 5
You need to take the square root of both sides. Consider the +/- then add 5
收錄日期: 2021-05-01 12:42:27
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