幾個MATHS問題~~~~

由於B<A :
A = B+1
B的一半比A的四分一多1 :
B/2 = A/4 + 1
B/2 = (B+1)/4 + 1
2B = B+1 + 4
B = 5
A = B+1 = 6

設B+1=A................(1)
B/2=A/4+1..............(2)
將(1)代入(2)：
..............B/2=(B+1)/4+1
...............2B=(B+1)+4
.................B=5
.............B+1=6
.................A=6
所以A是6，B是5。