How would you solve this problem? (solve this equation for x)?

3x^2 = - 72
x^2 = - 24
x = ± i √24
x = ± i 2 √6

Perhaps the question is meant to read as :-

3x^2 + 24 x = - 48

x^2 + 8x + 16 = 0

( x + 4 )^2 = 0

x = - 4

3x² + 24 = - 48
x² + 8 = - 16
x² = - 24
x = ± 24i or ± √- 24

Answer: x = ± 24i or ± √- 24—imaginary solutions only.

3x^2+24=-48=>
3x^2=-72=>
x^2=-24=>
x=2sqrt(6)i or -2sqrt(6)i
where i^2=-1.

3x^2+24=-48
Subtract 24 from both sides
3x^2 + 24 - 24 = - 48 - 24
3x^2 = - 72
Divide by three
x^2 = -24
taking sq rt
x = √-24
= 2i√6 or - 2i√6 (Answer)
There is no real solution.

Are you sure about that equation? The answer would be an imaginary number since you will have x^2 on one side of the equation and a negative number on the other.

3x^2 = -72
x^2 = -24
x = +/- sqrt(-24) = +/- i*sqrt(24) = +/- 2*i*sqrt(6)

sqrt is square root

3x^2+24=-48
3x^2=-72
x^2=-24
x= ± 2√6 i

3x^2 + 24 = -48 (subtract 24 from both sides)

3x^2 = -72 (divide by 3)

x^2 = -24 (take the square root)

x = root (-24) = root (-1 * 4 * 6) =

+/- 2i*root (6)

3x^2 + 24 = -48
3x^2 = -24 - 48
x^2 = -72/3
x = ±√(-24)
x = ±√(i^2 * 2^2 * 6)
x = ±2i√6