Math 問題急(中二)

[匿名]

2009-08-26 4:44 am

1. Find two possible 3-digit deny numbers such that each of them can be converted into a 8-digit binary number and a 2-digit hexadecimal number.

2. Find two possible binary numbers which are divisible by both 6 and 8 when they are converted into denary numbers.

回答 (1)

用戶10012

2009-08-26 6:15 am

✔ 最佳答案

Q1. 8-digit binary no. is from 0 to 2^8, that is between 0 and 256.
2 digit hexadecimal no. is from 0 to 16^2, that is between 0 and 256.
So possible nos. are 100 and 200.
Q2.
LCM of 6 and 8 is 24. So 2 possible nos. divisible by 6 and 8 are 24 and 48.
So the 2 possible binary nos. are 11000( = 24) and 110000 ( = 48).

2009-08-25 22:19:33 補充：
Correction for Q1. 8-digit binary is between 2^7 and 2^8, that is between 128 and 256. 2 digit hexadecimal no. is between 16 and 16^2, that is 16 and 256. So answer should be 150 and 200, not 100 and 200, sorry.

2009-08-25 22:25:49 補充：
150 = 10010110, 150 = 96. 200 = 11001000 , 200 = C8.

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Math 問題 急(中二)

回答 (1)

Math 問題急(中二)