Solve the equation, where p and q are constants. (Express the answers in terms of p and q.)
x^2 - (p+q)x + (p+1)(q-1) = 0
Solve an equation~5marks
2009-08-26 2:31 am
回答 (1)
2009-08-26 3:05 am
✔ 最佳答案
x2 - (p + q)x + (p + 1)(q - 1) = 0[x - (p + 1)][x - (q - 1)] = 0
x = p + 1 or q - 1
參考: Myself
收錄日期: 2021-04-13 16:50:02
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https://hk.answers.yahoo.com/question/index?qid=20090825000051KK01747