can u factorise 2x^2-35x+98?
回答 (3)
2009-08-24 4:17 pm
✔ 最佳答案
x's=[35+&-(1225-784)^1/2]/4=14 & 7/22(x-14)(x-7/2)=
=(x-14)(2x-7)
God bless you.
2009-08-24 11:59 pm
2x^2 - 35x + 98
= 2x^2 - 7x - 28x + 98
= (2x^2 - 7x) - (28x - 98)
= x(2x - 7) - 14(2x - 7)
= (2x - 7)(x - 14)
= 2x^2 - 7x - 28x + 98
= (2x^2 - 7x) - (28x - 98)
= x(2x - 7) - 14(2x - 7)
= (2x - 7)(x - 14)
2009-08-24 11:11 pm
(2x - 7)(x - 14)
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