1/4(3/y+2)=7,how do you solve?

y = 3/26
...which is 0.115384615 with all repeating except the first "1".

To solve 1/4 (3/y+2) = 7...

Multiply both sides by 4 to get rid of the parentheses:
3/y+2 = 28

Subtract 2 from both sides to get the variable term by itself:
3/y = 26

When x/y=z, x/z = y. So since 3/y=26...
3/26 = y
y = 3/26

1/4(3/y + 2)=7

(3/y + 2)=28

3/y=26

y=3/26

1/4[3/(y + 2)] = 7
3/(y + 2) = 7/(1/4)
3/(y + 2) = 7(4)
3 = 28(y + 2)
3 = 28(y) + 28(2)
3 = 28y + 56
28y = 3 - 56
y = -53/28

(3/y+2)=7*4


3/y=7*4 -2


3/y=26

y=3/26

times each side by 4
3/y+2=28
subtract 2
3/y=26
times each side by y
3=26y
divide by 26
3/26=y

3/y + 2 = 28
3/y = 26
y = 3/26