1/4(3/y+2)=7,how do you solve?
回答 (6)
2009-08-22 7:43 am
✔ 最佳答案
y = 3/26...which is 0.115384615 with all repeating except the first "1".
To solve 1/4 (3/y+2) = 7...
Multiply both sides by 4 to get rid of the parentheses:
3/y+2 = 28
Subtract 2 from both sides to get the variable term by itself:
3/y = 26
When x/y=z, x/z = y. So since 3/y=26...
3/26 = y
y = 3/26
2009-08-22 2:56 pm
1/4[3/(y + 2)] = 7
3/(y + 2) = 7/(1/4)
3/(y + 2) = 7(4)
3 = 28(y + 2)
3 = 28(y) + 28(2)
3 = 28y + 56
28y = 3 - 56
y = -53/28
3/(y + 2) = 7/(1/4)
3/(y + 2) = 7(4)
3 = 28(y + 2)
3 = 28(y) + 28(2)
3 = 28y + 56
28y = 3 - 56
y = -53/28
2009-08-22 2:47 pm
(3/y+2)=7*4
3/y=7*4 -2
3/y=26
y=3/26
3/y=7*4 -2
3/y=26
y=3/26
2009-08-22 2:37 pm
times each side by 4
3/y+2=28
subtract 2
3/y=26
times each side by y
3=26y
divide by 26
3/26=y
3/y+2=28
subtract 2
3/y=26
times each side by y
3=26y
divide by 26
3/26=y
2009-08-22 2:37 pm
3/y + 2 = 28
3/y = 26
y = 3/26
3/y = 26
y = 3/26
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