How do you solve the equation 3x^4/3 - 7 = 41?
回答 (3)
2009-08-21 5:56 pm
✔ 最佳答案
3x^(4/3) - 7 = 413x^(4/3) = 41 + 7
x^(4/3) = 48/3
x^(4/3) = 16
x = 16^(3/4)
x = (2^4)^(3/4)
x = 2^(4 * 3/4)
x = 2^3
x = 8
-- or --
x = 16^(3/4)
x = [(-2)^4]^(3/4)
x = (-2)^3
x = -8
2009-08-22 12:46 am
3x^4/3 – 7 = 41
3x^4/3 = 41 + 7
3x^4/3 = 48
x^4/3 = 16
x = 16^3/4
x = (4096)^(1/4)
x = â(â(4096))
x = â(±64)
x = ±8, ±8i
edit, correct arith mistake.
.
3x^4/3 = 41 + 7
3x^4/3 = 48
x^4/3 = 16
x = 16^3/4
x = (4096)^(1/4)
x = â(â(4096))
x = â(±64)
x = ±8, ±8i
edit, correct arith mistake.
.
2009-08-22 12:45 am
3x^4/3 - 7 = 41 .
3x^4/3 = 48
x^4/3 = 16
x = 16^3/4
x = 8 or x = -8
3x^4/3 = 48
x^4/3 = 16
x = 16^3/4
x = 8 or x = -8
收錄日期: 2021-05-01 12:41:24
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