If 2b^2 = a[(a - 2)^2 + b^2], show that a^2 + b^2 - 2a = 0.
Maths
2009-08-22 3:19 am
回答 (1)
2009-08-22 4:21 am
✔ 最佳答案
2b2 = a[(a - 2)2 + b2]2b2 = a(a - 2)2 + ab2
(2 - a)b2 = a(a - 2)2
a(a - 2)2 - (2 - a)b2 = 0
a(a - 2)2 + (a - 2)b2 = 0
(a - 2)[a(a - 2) + b2] = 0
(a - 2)(a2 + b2 - 2a) = 0
So, we get a2 + b2 - 2a = 0
參考: Physics king
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