a block of mass 6kg resting on a rough inclined plane. the angle of inclination of the plane is 30 degrees.
find the frictional force and the normal reaction acting on the block
physics
2009-08-21 3:59 am
回答 (2)
2009-08-21 6:19 pm
✔ 最佳答案
As the block is resting on the plane, by Newton's 1st law of motion, the net force acting on it is zero.So, frictional force = component of weight down the slope
= mgsin@
= (6)(10)sin30*
= 30 N
In this case, normal reaction = mgcos@
= (6)(10)cos30*
= 52.0 N
參考: Physics king
2009-08-21 4:36 am
the frictional force=30N
the normal reaction acting on the block=30√3N
the normal reaction acting on the block=30√3N
收錄日期: 2021-04-19 15:11:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20090820000051KK02000