(-2) + n x (-3) = +10 ? Help!?

-2 + (-3)n = 10
-2 - 3n = 10
-3n = 2 + 10
n = 12/(-3)
n = -4

Hey there- hope this helps :) We need to factorise the denominator x²-7x+10 of this equation. So we're looking for 2 numbers. When we multiply them they must equal 10 and when we add them they must give -7. After a couple of miontues, we can work out these factorising number should be -2 and -5. so (x²-5x)(-2x+10) = x(x-5) -2(x-5) So...we see that (x-2) (x-5) are the factors so x²-7x+10 = (x-2)(x-5) 3(x-2) ----------- (x-5) (x-2) The (x-2) can cancel and u are left with: 3 ---- (x-5)

In that case, n can be two factors. Let n= 3 and the value of x is 5. Let n = 5 and the value of x is 3.

(-2)+nx(-3)=10

Remove the parentheses around the expression -2.
-2+nx(-3)=10

Multiply nx by each term inside the parentheses.
-2-3nx=10

Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides.
-3nx=2+10

Add 10 to 2 to get 12.
-3nx=12

Divide each term in the equation by -3x.
-(3nx)/(-3x)=(12)/(-3x)

Simplify the left-hand side of the equation by canceling the common terms.
n=(12)/(-3x)

Simplify the right-hand side of the equation by simplifying each term.
n=-(4)/(x)

Here's your answer:

http://www.youtube.com/watch?v=CWH5ZfdWm5o&feature=related

- 2 - 3 n = 10

- 12 = 3 n

n = - 4