can somone help me with this math question?

2009-08-19 10:09 am
[41-(6+9) divided by 5] - [48 divided (20-8)]....I can't seem to figure it out. I would appreciate it. Thanks

回答 (9)

2009-08-19 10:16 am
✔ 最佳答案
as written by you
[41 - (6+9) divided by 5] - [48 divided by (20-8)]

open inner brackets first
= [41 - 15 divided by 5] - [48 divided by 12]

next do division
= [41 - 3] - [4]

finally do subtraction
= 34
2009-08-19 7:41 pm
[ 41 - (15) / 5 ] - [ 48 / 12 ]

[ 41 - 3 ] - 4

38 - 4

34
2009-08-19 10:34 am
Some use BODMAS, but a more correct way is:
First brackets within brackets, then brackets, then
exponents, then
Multiplication and division
then addition and subtraction.
When dealing with equal precedence (multiplication and division have equal precedence and also addition and subtraction have equal precedence) read from left to right.
(41 - 15divided by5) - (48divided by 12)
=(41-3) - 4
=38 - 4 =34
參考: Was a math teacher
2009-08-19 10:22 am
((41 - (6+9)/5 - ((48)/(20 - 8))
= ((41 - 15)/5 - ((48)/12
= ((26/5) -4
= 5.2 - 4
= 1.2
參考: my own knowledge
2009-08-19 10:20 am
[41 - (6 + 9)/5] - [48/(20 - 8)]
= [41 - 15/5] - [48/12]
= 41 - 3 - 4
= 38 - 4
= 34
2009-08-19 10:20 am
41-15=26
26/5=5.2
-----------------------
48/12=4
2009-08-19 10:17 am
i take it as [41-((6+9)/5)]
[41-(15/5)]-[48/12]
[41-3]-[4]

41-3-4=34.
2009-08-19 10:15 am
minus 9.96
2009-08-19 10:14 am
the answer is a number


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