Let 1,x1,x2,25 and 1,y1,y2,y3,25 be two arithmetic progression.
(x2-x1)/(y3-y2)=
A.0
B.4/3
C.1
D.4/5
Maths~!
2009-08-20 6:47 am
回答 (3)
2009-08-20 6:55 am
✔ 最佳答案
First sequence, 25 – 1 = 3d1 => d1 = 8Second sequence, 25 – 1 = 4d2 => d2 = 6
x2 – x1 = d1
y3 – y2 = d2
d1/d2 = 8/6 = 4/3 (B)
2009-08-20 7:12 am
可先求出x1,x2,y2,y3的值
2009-08-20 6:57 am
1,x1,x2,25 = 1, 9, 17, 25 (The differnece is 8)
1,y1,y2,y3,25 = 1, 7, 13, 19, 25 (The difference is 6)
So, (x2-x1)/(y3-y2)= (17-9)/(19-13)
= 8/6
= 4/3
The answer is B
1,y1,y2,y3,25 = 1, 7, 13, 19, 25 (The difference is 6)
So, (x2-x1)/(y3-y2)= (17-9)/(19-13)
= 8/6
= 4/3
The answer is B
參考: me
收錄日期: 2021-04-22 00:45:11
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