5x-4(6+2x) < 2(1-x)
How do I get x?
5x-4(6+2x) < 2(1-x) ---how do I get x?
2009-08-18 6:30 am
回答 (5)
2009-08-18 6:34 am
✔ 最佳答案
Distribute the -4 and the 2, then move all "x" terms to the left. Move all constants to the right. Simplify, and solve for x.5x - 24 - 8x < 2 - 2x
5x - 24 - 8x + 2x < 2
5x - 8x + 2x < 2 + 24
-x < 26
x > -26
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2009-08-18 1:33 pm
5x - 24 -8x < 2 - 2x
So
-3x < 26 - 2x
-x < 26
So x > -26
So
-3x < 26 - 2x
-x < 26
So x > -26
2009-08-18 5:05 pm
5 x - 24 - 8 x < 2 - 2 x
- 26 < x
x > - 26
- 26 < x
x > - 26
2009-08-18 1:46 pm
5x - 4(6 + 2x) < 2(1 - x)
5x - 4(6) - 4(2x) < 2(1) - 2(x)
5x - 24 - 8x < 2 - 2x
5x - 8x + 2x < 2 + 24
-x < 26
x > 26/(-1)
x > -26
5x - 4(6) - 4(2x) < 2(1) - 2(x)
5x - 24 - 8x < 2 - 2x
5x - 8x + 2x < 2 + 24
-x < 26
x > 26/(-1)
x > -26
2009-08-18 1:36 pm
First, expand as such:
5x - 4(6+2x) < 2(1-x)
5x - 24 - 8x < 2 - 2x
-3x -24 < 2-2x
Now, add 2x to both sides to get:
2x - 3x - 24 < 2 - 2x + 2x
-x - 24 < 2
now, add 24 to both sides to get:
-x - 24 + 24 < 2 + 24
-x < 26
Now, multiply through by -1 to change the sign of the x variable:
x > -26
5x - 4(6+2x) < 2(1-x)
5x - 24 - 8x < 2 - 2x
-3x -24 < 2-2x
Now, add 2x to both sides to get:
2x - 3x - 24 < 2 - 2x + 2x
-x - 24 < 2
now, add 24 to both sides to get:
-x - 24 + 24 < 2 + 24
-x < 26
Now, multiply through by -1 to change the sign of the x variable:
x > -26
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