1 math question only! Help!

2009-08-13 7:40 pm
Please help me!! ><

How many 5-card hands from a 52-card deck contain a Full House (i.e. three of a kind and a pair)?

(use nCr to calculate, or just factorials)
Thanks a lot!!

回答 (1)

2009-08-13 9:22 pm
✔ 最佳答案
There are 13 choices for the value of the triple.
There are 12 choices for the value of the pair.

For colour: There are: C(4,3) = 4 ways to get the triple and there are: C(4,2) = 6 ways to get the pair.

Therefore, there are : 13 12 4 6 = 3,744 possible Full Houses.

The probability of being dealt a full house

P(Full House) = 3,744 / 2,598,960 = 78 / 54,145 = 0.00144057623


2009-08-13 13:23:03 補充:
13*12*4*6


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