help with algebraic factoring?
回答 (3)
2009-08-13 7:23 am
✔ 最佳答案
Unless you are familiar with complex numbersthen, =(7a-4i)(7a+4i)
whilst i^2=-1
God bless you.
2009-08-13 7:53 am
If you can only factor it with real numbers, then you are right. However, you can factor it with complex numbers.
49a^2 + 16
= (7a)^2 - (-16)
= (7a)^2 - (i^2 * 4^2)
= (7a)^2 - (4i)^2
= (7a + 4i)(7a - 4i)
49a^2 + 16
= (7a)^2 - (-16)
= (7a)^2 - (i^2 * 4^2)
= (7a)^2 - (4i)^2
= (7a + 4i)(7a - 4i)
2009-08-13 7:15 am
ya that can't be factored all you can do is isolate 49a^2=-16 then square both sides to get rid of the square and go from there
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