✔ 最佳答案
The tension in the string is mg (which equals to the weight of the particle hung below the ring).
Let the angle between the string and the vertical be θ.
tanθ = (h/2)/h = 1/2
Resolving horizontal force,
Tsinθ = 2mω2r where r = h/2
mg(1/√5) = mω2h
ω2 = g/(√5h)
2π / Period = √ [g/(√5h)]
Period = 2π√(√5h/g)